Answer:
$510
Explanation:
Let X be the amount of money that insurance company will have to pay on the policy for home.
It is given that according to experience, may sustain a total loss in a given year with probability of .001 and a 50% loss with probability .01. Ignoring all other partial losses.
It means the possible values for variable X are 0, 42500 and 85000.
![P(X=42500)=0.01](https://img.qammunity.org/2020/formulas/mathematics/college/rve3v5pcy156abfs82o9h3orh37a4taim1.png)
![P(X=85000)=0.001](https://img.qammunity.org/2020/formulas/mathematics/college/g500dtrbthacr6ogkjqvhy7btj5y0akcbz.png)
We have only three possible values of X. So,
![P(X=0)+P(X=42500)+P(X=85000)=1](https://img.qammunity.org/2020/formulas/mathematics/college/7j4rbidur02vd5le2lpgbf64ok8uiynv80.png)
![P(X=0)=1-0.01-0.001=0.989](https://img.qammunity.org/2020/formulas/mathematics/college/zqfuav79nz5t40prybe36hrpwhmtuwwipr.png)
The expected amount of money is
![E(X)=\sum xP(x)](https://img.qammunity.org/2020/formulas/mathematics/college/wzeimq4n3a4a7gf4yeyk3m1okx6v43eie4.png)
![E(X)=0\cdot P(X=0)+42500\cdot P(X=42500)+85000\cdot P(X=85000)](https://img.qammunity.org/2020/formulas/mathematics/college/s1vdu6s7gk3ls2b32jwtayb8ijncp8gqtz.png)
![E(X)=0\cdot (0.989)+42500\cdot (0.01)+85000\cdot (0.001)](https://img.qammunity.org/2020/formulas/mathematics/college/bxds87sx4p6vp57x9xgxaiofoivpiz3dzh.png)
![E(X)=0+425+85](https://img.qammunity.org/2020/formulas/mathematics/college/6xpwf463a104ajovb0an4wbgjcubffj8s2.png)
![E(X)=510](https://img.qammunity.org/2020/formulas/mathematics/college/zuil0ndb1yplgolqgf47yqz5qq2qalqp9j.png)
Therefore, the insurance company should charge a premium of $510 for a yearly policy in order to break even on all $85,000 policies in this area.