Question

Calculate AS per mole for the melting of Hg at -38°C, AH fus = 2.3 kJ/mol. J/mol K

Answer 1

Answer : The value of change in entropy for melting of Hg is 9.8 J/mol.K

Explanation :

Formula used :

`\Delta S=(\Delta H_(fus))/(T_m)`

where,

`\Delta S` = change in entropy

`\Delta H_(fus)` = change in enthalpy of fusion = 2.3 kJ/mol

`T_m` = melting point temperature =
`-38^oC=273+(-38)=235K`

Now put all the given values in the above formula, we get:

`\Delta S=(\Delta H_(fus))/(T_m)`

`\Delta S=(2.3kJ/mol)/(235K)`

`\Delta S=(2.3* 10^3J/mol)/(235K)`

`\Delta S=9.8J/mol.K`

Therefore, the value of change in entropy for melting of Hg is 9.8 J/mol.K