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What are the real zeros of x3 + 4x2 − 9x − 36?

A. 1, 2, 3

B. -6, 2, 3

C. –4, –3, 3

D. –1, 2, 18

User Quento
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1 Answer

6 votes

Answer:

C

Explanation:

x^3+4x^2-9x-36=0

or x²(x+4)-9(x+4)=0

or (x+4)(x²-9)=0

or (x+4)(x+3)(x-3)=0

x=-4,-3 or 3

User Finkelson
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