Question

A ball rolling up a hill decelerates with a magnitude of 4 m/s^2. What was its starting velocity if the ball rolls to a stop after traveling 22m?

Answer 1

13.26m/s

Step-by-step explanation:

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follow

`\frac {Vf^(2)-Vo^2}{2.a} =X\\`

Where

Vf = final speed

=0m/s

Vo = Initial speed

A = acceleration

=-4m/s^2

X = displacement

=22m

solving for v0

`Vo=√(Vf^2-2ax) \\Vo=√((0)^2-2(-4)(22))\\Vo=13.26m/s`

the starting velocity of the ball is 13.26m/s