Question

10. Eddie and his sister walked from home to school. His sister started walking at 8.00 am at an average speed of 50 m/min. Eddie started walking at 8.05 am at a speed of 60 m/min. Eddie caught up with his sister at mid-point between the school and his home. Find the distance between Eddie's home and the school.

Answer 1

The distance between Eddie's home and the school is 3000 m

Explanation:

Consider the provided information.

His sister started walking at 8.00 am at an average speed of 50 m/min. Eddie started walking at 8.05 am at a speed of 60 m/min. Eddie caught up with his sister at mid-point between the school and his home.

Let the distance between school and home is x.

Let t is the time taken by Eddie sister to reach at mid-point between school and home.

Eddie caught up with his sister at mid-point between the school and his home.

That means his sister covers x/2 distance.

`Time=(Distance)/(Speed)`

Speed of Eddie sister is 50 m/min.

`t=((x)/(2))/(50)` .....(1)

Eddie started walking at 8.05 am at a speed of 60 m/min.

`t-5=((x)/(2))/(60)`

`t=((x)/(2))/(60)+5` .....(1)

Equate both the equation as shown:

`((x)/(2))/(50)=((x)/(2))/(60)+5`

`(x)/(100)=(x)/(120)+5`

`(x)/(100)-(x)/(120)=5`

`(12x-10x)/(1200)=5`

`2x=6000`

`x=3000`

Hence, the distance between Eddie's home and the school is 3000 m