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A rigid container equipped with a stirring device contains 2.8 kg of motor oil. Determine the rate of specific energy increase when heat is transferred to the oil at a rate of 1 W, and 1.5 W of power is applied to the stirring device. (Round the final answer to one decimal place.)

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Answer:

Rate of change of specific energy will be
=(2.5)/(2.8)=0.8928j/kgsec

Step-by-step explanation:

We have given mass of the motor oil m = 2.8 kg

Heat is transferred to the oil at a rate Q = 1 W

Power supply by stemming device
W=-1.5Watt

Applying first law to the device


Q=W+dU


1=-1.5+dU


dU=2.5

Rate of change of specific energy will be
=(2.5)/(2.8)=0.8928j/kgsec

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