Question

Can someone help
please the answers i put are displayed i dont know what im doing wrong

Answer 1

3360 m

Step-by-step explanation:

The first plane has a velocity of 660 m/h at a heading of 34.9°.

After 3 hours, the horizontal displacement is:

x₁ = (660 cos 34.9° m/h) (3 h)

x₁ = 1623.9 m

And the vertical displacement is:

y₁ = (660 sin 34.9° m/h) (3 h)

y₁ = 1132.8 m

Similarly, for the second plane:

x₂ = (560 cos 168° m/h) (3 h)

x₂ = -1643.3 m

y₂ = (560 sin 168° m/h) (3 h)

y₂ = 349.3 m

The horizontal distance between them is:

x = x₁ − x₂

x = 1623.9 m − (-1643.3 m)

x = 3267.2 m

And the vertical distance between them is:

y = y₁ − y₂

y = 1132.8 m − 349.3 m

y = 783.5 m

So the overall distance is:

d² = x² + y²

d² = (3267.2 m)² + (783.5 m)²

d = 3359.8 m

Rounding, the distance between them after 3 hours is approximately 3360 m.