Question

A point charge with a charge q1 = 4.00 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC moves from the point x= 0.170 m , y=0 to the point x= 0.270 m , y= 0.270 m. How much work is done by the electric force on q2?

Answer 1

W = -0.480 J

Step-by-step explanation:

given,

q₁ = 4 μC

q₂ = -4.10 μC

`W = kq_1q_2((1)/(a)+(1)/(b))`

`b = √((0.27-0)^2+(0.27-0)^2)`

b = 0.381

k = 8.99 × 10⁹ Nm²/C²

`W = 8.99* 10^9* 4* 10^(-6)* (-4.1 * 10^(-6))((1)/(0.17)+(1)/(0.381))`

`W = [-147.436* (5.88-2.62)* 10^(-3)]J`

W = -0.480 J

Work done by the electric force W = -0.480 J