ANSWER:
Standard deviation of 2, 4, 7, 8, 9 is 2.6
SOLUTION:
Given, data set is 2, 4, 7, 8, 9.
We know that, Standard deviation is given by
![\sigma=\sqrt{(\Sigma(X i-\mu)^ 2)/(n)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/io9yk4dxzje7tua5xzs8hwc5m3v7n7vaem.png)
Where,
is element of data set
is mean of data set
n is total number observations.
Now, mean is given by
![\mu=\frac{s u m o f \text { observations }}{\text {number of observations}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/phnlnx7ft5arlamqv0sjjxuk35qvrc9ekg.png)
![\begin{array}{l}{=(2+4+7+8+9)/(5)} \\\\ {=(30)/(5)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rlyie66ybxf36bmlykxb79isbwwx5tibkj.png)
= 6
So, the mean of data set is 6.
Now, standard deviation,
![\sigma=\sqrt{((2-6)^2+(4-6)^2+(7-6)^2+(8-6)^2+(9-6)^2)/(5)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jmimh5cc9jtxsqkgigllnua1twpuidptiu.png)
![\sigma=\sqrt{((-4)^2+(-2)^2+(1)^2+(2)^2+(3)^2)/(5)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hldi6nrj5wmkbjnwzw6i7n0s41ijecx5mb.png)
![\begin{array}{l}{\sigma=\sqrt{(16+4+1+4+9)/(5)}} \\\\ {\sigma=\sqrt{(34)/(5)}} \\\\ {\sigma=√(6.8)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/49jn8ucgenfskjisc9ide48npidnnwe9jj.png)
So, the standard deviation is 2.607 approximately.
When rounded to nearest tenth answer is 2.6