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A 0.907 mole sample of ideal gas at 12c occupies a volume of 4.25L. What is the pressure of gas?

1 Answer

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Pressure of the ideal gas=505.7kPa

Given:

No of moles=0.907mole

Temperature of the gas=
12^(\circ) \mathrm{C}

Volume of the gas=4.25L

To find:

Pressure of the gas

Step by Step Explanation:

Solution:

According to the ideal gas equation


P V=n R T
and from this pressure is derived as


P=(n R T)/(V)

Where P=Pressure of the gas

V=Volume of the gas=4.25L

n=No of the moles=0.907mole

R=Gas constant=8.314
J / m o l^(-1) K^(-1)

T=Temperature of the gas=
12^(\circ) \mathrm{C} =273+12=285K

Substitute these known values in the above equation we get


P=(0.907 * 8.314 * 285)/(4.25)


P=(2149.13)/(4.25)

P=505.7kPa

Result:

Thus the pressure of the ideal gas is 505.7kPa

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