Question

A 0.907 mole sample of ideal gas at 12c occupies a volume of 4.25L. What is the pressure of gas?

Answer 1

Pressure of the ideal gas=505.7kPa

Given:

No of moles=0.907mole

Temperature of the gas=
`12^(\circ) \mathrm{C}`

Volume of the gas=4.25L

To find:

Pressure of the gas

Step by Step Explanation:

Solution:

According to the ideal gas equation

`P V=n R T` and from this pressure is derived as

`P=(n R T)/(V)`

Where P=Pressure of the gas

V=Volume of the gas=4.25L

n=No of the moles=0.907mole

R=Gas constant=8.314
`J / m o l^(-1) K^(-1)`

T=Temperature of the gas=
`12^(\circ) \mathrm{C}` =273+12=285K

Substitute these known values in the above equation we get

`P=(0.907 * 8.314 * 285)/(4.25)`

`P=(2149.13)/(4.25)`

P=505.7kPa

Result:

Thus the pressure of the ideal gas is 505.7kPa