Answer: 0.893
Explanation:
Given : Sample size of residential water bills: n=100
Number of residences had reduced their water consumption over that of the previous year = 80
Then sample proportion:
![\hat{p}=(80)/(100)=0.8](https://img.qammunity.org/2020/formulas/mathematics/college/buev55aqis4ig6k9tgci8m222sivdlkivl.png)
Critical value for 98% confidence=
![z_(\alpha/2)=2.326](https://img.qammunity.org/2020/formulas/mathematics/college/yuwidokmfa56sedpwrebbp4g2kyzx1cuyv.png)
The upper bound for confidence interval for population proportion :
![\hat{p}+ z_(\alpha/2)\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}](https://img.qammunity.org/2020/formulas/mathematics/college/w05azqcn000zn9kh8xjwpdgitck63j1fha.png)
![=0.8+ (2.326)\sqrt{(0.8(1-0.8))/(100)}\\\\=0.8+0.09304=0.89304\approx0.893](https://img.qammunity.org/2020/formulas/mathematics/college/9w9wsohrjzliqgabtz9cy4f6ne82otr5l8.png)
Hence, the 98% upper confidence bound for the proportion of residences that reduced their water consumption.=0.893