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During a recent drought, a water utility in a certain town sampled 100 residential water bills and found that 80 of the residences had reduced their water consumption over that of the previous year. Find a 98% upper confidence bound for the proportion of residences that reduced their water consumption. Round the answer to three decimal places.

User Caleth
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Answer: 0.893

Explanation:

Given : Sample size of residential water bills: n=100

Number of residences had reduced their water consumption over that of the previous year = 80

Then sample proportion:
\hat{p}=(80)/(100)=0.8

Critical value for 98% confidence=
z_(\alpha/2)=2.326

The upper bound for confidence interval for population proportion :


\hat{p}+ z_(\alpha/2)\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}


=0.8+ (2.326)\sqrt{(0.8(1-0.8))/(100)}\\\\=0.8+0.09304=0.89304\approx0.893

Hence, the 98% upper confidence bound for the proportion of residences that reduced their water consumption.=0.893

User KayakinKoder
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