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A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a 1.19 meter high desk. How far away does the book land?

User Stonebig
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A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a 1.19 meter high desk. The book lands at 2.45 m.

Answer: 2.45 m

Step-by-step explanation:

The book when pushed with the initial velocity of 5 m/s, the book flights down from the high desk which is 1.19 m high. The book takes the projectile motion path and hence to calculate the distance, how far it lands away from the desk can be calculated as follows,

Given that,

v = 5 m/s

h = 1.19 m

As we know that the time can be calculated as the time of flight, by


T=\sqrt{(2 h)/(g)}

Putting the values, we get,


T=\sqrt{(2 * 1.19)/(9.8)}=0.49 \mathrm{sec}

Thereby,


\text {distance}=\text {velocity } * \text {time}=5 * 0.49=2.45 \mathrm{m}

User Damara
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