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You’ve experienced convection cooling if you’ve ever extended your hand out the window of a moving vehicle or into a flowing water stream. With the surface of your hand at a temperature of 30°C, consider the two following conditions.

Condition A: a vehicle speed of 35 km/h in air at -5°C with a convection coefficient of 40 W/m2·K.
Condition B: a velocity of 0.2 m/s in a water stream at 10°C with a convection coefficient of 800 W/m2·K.

What is the convection heat flux for these two condition?

User Sanchez
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Answer:

Condition A

Heat flux is 1400 W/M^2

Condition B

Heat flux is 12800 w/m^2

Step-by-step explanation:

Given that:


T_s is given as 30 degree celcius

condition A

Air temperature = - 5 degree c

convection coefficient h = 40 w/m^2. k


heat\ flux = (Q)/(a)= h\Delta = 40{30 - (-5)} = 1400 w/m^2

condition A

water temperature = 10 degree c

convection coefficient = 800 w/m^2.k


heat\ flux = (Q)/(A) = H(\Delta} = 800* (30-14) = 12800w/m^2

User Eunsook
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