Question

Michael analyzes a Chemical and determines it is calcium chloride (CaCl). After further tests, Michael declares that calcium chloride is a salt and has no effect on pH.

A. ____ This means that the Chemical Will release:

(A) only H= ions into water.

(B) only OH - ions into water.

(C) Equal amounts of OH- and H+ ions into water.

(D) neither OH- or H+ ions into water.

B. When placed in water, wha ions does this Chemical release?

Answer 1

D Neither OH- or H+ ions into water,

B Ca2+ and Cl- ions are released.

Step-by-step explanation:

The salt breaks up into calcium and chloride ions.

Answer 2

A)

Solution:

Salt is formed when an acid reacts with a base. We call this reaction as a Neutralization reaction.

For example

`NaOH+HCl>NaCl+H_2O`

`CaCl_2` is formed from a strong base
`Ca(OH)_2` and strong acid HCl as shown in the Equation

`Ca(OH)_2+2HCl>CaCl_2+2H_2 O`

`CaCl_2` is a salt which produces ions
`Ca^(2+)` and
`Cl^-` ions into water

So the Answer is option D

Neither
`OH^-` or
`H^+` ions into water.

B)

Solution:

Arrhenius Theory: An acid is a substance which produces one or more hydrogen ions, (H+) in aqueous solution.

Examples:

`HCl(aq)>H^+(aq)+Cl^-(aq)\\\\HBr(aq)>H^+(aq)+Br^- (aq)\\\\H_2SO_4(aq)>2H^+(aq)+SO_4^(2-)(aq)\\\\H_3 PO_4(aq)>3H^+(aq)+PO_4^(-3)(aq)\\\\CH_3COOH(aq)>CH_3 COO^-(aq)+H^+(aq)`

A Base is a substance which produces one or more hydroxyl ion or hydroxide ion (OH-) in aqueous solution.

Examples

`KOH(s)> K^+(aq) +OH^-(aq)\\\\Ca(OH)_2(s)>Ca^(2+)(aq)+2OH^- (aq)\\\\Al(OH)_3 (s)> Al^(3+)(aq)+3OH^- (aq)`

Please note: (aq) stands for aqueous which means in the presence of water that is, water acts as a solvent.

`CaCl_2` is formed from a strong base
`Ca(OH)_2` and strong acid HCl as shown in the Equation

`Ca(OH)_2+2HCl>CaCl_2+2H_2 O`

So when placed in water
`CaCl_2` as it is formed from a strong base it releases OH- ions and as it is formed from a strong acid it releases H+ ions .

So, option C is the Answer

Equal amounts of OH- and H+ ions into water