Question

A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much force pulls the wagon forward?

245 N

220 N

330 N

110 N

Answer 1

The wagon is pulled by a force of 245.2377 N ~ 245 N, when the man pulls with 330 N of force at an angle of 42° with the ground.

Explanation :

The horse pulls the wagon at an angle of 42°. The angle is made along the horizontal parallel to ground surface.

On resolving the force (the pull) into its components, we get

`F_x` = Horizontal force = 330
`* \cos 42^(\circ)`= 245.2377 N

`F_y` = Vertical force = 330
`* \sin 42^(\circ)`= 220.813 N

For the Wagon to get pulled, we require
`F_x` (Horizontal force)

Therefore,

Force =
`F_x` = 245.2377 ~ 245 N

Answer 2

245N

Step-by-step explanation:

We just need to multiply the force the man pulls the wagon by the cosine of the angle with the ground.

F = 330N * cos(42°) = 245.2N