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What is true about △ABC? Select three options

A) AB ⊥ AC
B) The triangle is a right triangle.
C) The triangle is an isosceles triangle.
D) The triangle is an equilateral triangle.
E) BC ∥ AC

What is true about △ABC? Select three options A) AB ⊥ AC B) The triangle is a right-example-1
User Imgen
by
7.8k points

2 Answers

3 votes

Answer:i think its a,b,c

Explanation:

User Daniel Azuma
by
8.2k points
1 vote

Answer:

A) AB ⊥ AC

B) The triangle is a right triangle.

C) The triangle is an isosceles triangle

Explanation:

we know that

the formula to calculate the distance between two points is equal to


d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}

step 1

Find the distance AB

we have


A(-1,3), B(-5,-1)

substitute in the formula


d=\sqrt{(-1-3)^(2)+(-5+1)^(2)}


d=\sqrt{(-4)^(2)+(-4)^(2)}


d_A_B=√(32)\ units

step 2

Find the distance BC

we have


B(-5,-1),C(3,-1)

substitute in the formula


d=\sqrt{(-1+1)^(2)+(3+5)^(2)}


d=\sqrt{(0)^(2)+(8)^(2)}


d_B_C=8\ units

step 3

Find the distance AC

we have


A(-1,3),C(3,-1)

substitute in the formula


d=\sqrt{(-1-3)^(2)+(3+1)^(2)}


d=\sqrt{(-4)^(2)+(4)^(2)}


d_A_C=√(32)\ units

step 4

Compare the length sides of triangle


d_A_B=√(32)\ units


d_B_C=8\ units


d_A_C=√(32)\ units

therefore

The triangle ABC is an isosceles triangle, because has two equal sides

The triangle ABC is a right triangle because satisfy the Pythagoras theorem


BC^2=AB^2+AC^2


8^2=(√(32))^2+(√(32))^2


64=32+32


64=64 ----> is true (Is a right triangle)

AB ⊥ AC because in a right triangle the legs are perpendicular

User Alan Carwile
by
8.1k points
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