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The sum of two integers is 60 and their difference is 4. Find the integers

User M G
by
7.7k points

2 Answers

1 vote

Answer:

28 and 32

Explanation:

28 plus 32 equals 60 and 32 minus 28 equals 4.

User Pauloco
by
8.0k points
3 votes

Answer:

The integers are 32 and 28 .

Solution:

Let the two integers be x and y.

It is given that sum of two integers is 60. Writing it in equation form we get,


x + y = 60 ……………..(Let this be equation 1)

Again it is given that, the difference between the two integers is 4. Writing it in equation form we get,


x-y=4………………….(let this be equation 2)

Adding Equation 1 and equation 2 we get,


x+y+x-y=60+4


\Rightarrow 2 x=64


\Rightarrow \mathrm{x}=(64)/(2)


\Rightarrow x=32

Substituting the value of x = 32 in equation 2 we get


32-y=4


\Rightarrow 32-4=y


\Rightarrow 28=\mathrm{y}

Therefore, the two integers are 32 and 28.

User Wachme
by
8.6k points

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