Answer:
When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules
Solution:
We know
![\text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})*\text { Distance (D) }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ajghoap8nkj21zgrcd6b445wmj0hew2spm.png)
Anne is pushing the wheelbarrow with a force of 70 N at an angle of
with the horizontal
So the force of Anne will be
![F=70 \cos 50^(\circ)=(70 * 0.64)=44.8 \mathrm{N}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9mxyxd507oteifjg5h8w1q2dm4sz5spv5p.png)
She pushes the wheelbarrow 25 meter, So D = 25 meters
So, the
![work,F* D=(44.8 * 25)=1120 \text { Joules }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4nda5q28edc5xnqxltvj2ecv5pcrhm5354.png)
Anne has done total 1120 joules work.