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Quadratic formula for 2x^+5x-7

User Bamsworld
by
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1 Answer

5 votes

Answer:

x = -(7/2)^(1/6) or x = (7/2)^(1/6) or x = -(-1)^(1/3) (7/2)^(1/6) or x = (-1)^(1/3) (7/2)^(1/6) or x = -(-1)^(2/3) (7/2)^(1/6) or x = (-1)^(2/3) (7/2)^(1/6)

Explanation:

Solve for x:

2 x^6 - 7 = 0

Add 7 to both sides:

2 x^6 = 7

Divide both sides by 2:

x^6 = 7/2

Taking 6^th roots gives (7/2)^(1/6) times the 6^th roots of unity:

Answer: x = -(7/2)^(1/6) or x = (7/2)^(1/6) or x = -(-1)^(1/3) (7/2)^(1/6) or x = (-1)^(1/3) (7/2)^(1/6) or x = -(-1)^(2/3) (7/2)^(1/6) or x = (-1)^(2/3) (7/2)^(1/6)

User Jason Youk
by
9.6k points

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