Question

What is the value of x+3y+z if x=3,y=3 and z=4

Answer 1

16

Explanation:

Answer 2

The value of the given equation
`x+3y+z` is 16

Solution:

Given values are x=3; y=3; z=4

To find: the value of
`x+3y+z`

On substituting the given values of x, y and z in the equation,

we get,
`3+(3*3)+4`

`\Rightarrow 3+9+4 = 16`

Hence, the value of
`x+3y+z` is 16