Question

How many solutions does this equation have?

-3c = 2c − 5c

Answer 1

One solutions

Explanation:

Isolate c on one side of the equation.

-3c=2c-5c

2c-5c=-3c (Combine like terms & group like terms.)

-3c=-3c

-3c+3c=-3c+3c (Add 3c from both sides.)

-3c+3c (Solve.)

-3c+3c=0

0=0

There are one solutions.

Answer 2

Answer: One solution

Step-by-step explanation: Numerator equal to zero (0): dividing zero (0) by any number is always equal to zero (0).

-3c=2c-5c

-3c-2c-5c=0: equal signs add up and keep the signal

-10c=0

0 = 0

10