Question

Is 5 a solution to the equation 3(x+1)=7(x-2)-3

Answer 1

yes

Explanation:

3x5=15

3x1=3 15+3=18

7x5=35

7x2=14 35-14=21 21-3=18

18=18

Answer 2

Proof:

Given
`3(x+1)=7(x-2)-3`

To prove that the solution of
`3(x+1)=7(x-2)-3` is 5,

`3(x+1)=7(x-2)-3`

On taking off the brackets we get,

`3x+3=7x-14-3`

On grouping the x terms together,

`7x-3x=14+3+3`

On solving we get,

`4x=20`

`x=(20)/(4)`

On dividing 20 by 4,

`x=5`

`\Rightarrow` Hence proved that the solution for
`\bold3(x+1)=7(x-2)-3\bold` is 5.