Question

a directed line segment AB on he coordinate plane starts from A (3, 0) and ends at B (12, -9). Find the y coordinate of point C on the line segment A that partitions the segment into a 6:5 ratio. The answer should be a single number . Round your answer to the nearest 10th if needed.

Answer 1

`\bf \textit{internal division of a line segment using ratios} \\\\\\ A(3,0)\qquad B(12,-9)\qquad \qquad \stackrel{\textit{ratio from A to B}}{6:5} \\\\\\ \cfrac{A\underline{C}}{\underline{C} B} = \cfrac{6}{5}\implies \cfrac{A}{B} = \cfrac{6}{5}\implies 5A=6B\implies 5(3,0)=6(12,-9)\\\\[-0.35em] ~\dotfill\\\\ C=\left(\frac{\textit{sum of`

`\bf C=\left(\cfrac{(5\cdot 3)+(6\cdot 12)}{6+5}\quad ,\quad \cfrac{(5\cdot 0)+(6\cdot -9)}{6+5}\right) \\\\\\ C=\left( \cfrac{15+72}{11}~~,~~\cfrac{0-54}{11} \right)\implies C\left(\qquad \qquad ~~,~~-\cfrac{54}{11} \right)`

Answer 2

The answer to your question is: y = -54 / 11

Explanation:

Data

A (3, 0)

B (12, -9)

r = 6/5

Formula

y =
`(y1 + ry2)/(1 +r)`

y =
`(0 + (6/5)(-9))/(1 + 6/5)`

y =
`(-54/ 5)/(11/5)`

y = -54/11