Answer:
The equation of the line passing through (0,0) and (4,3) is
![y=(3)/(4) x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/szpjaf1no13jf8dcuxmhyo1dtieomn2mqt.png)
Solution:
Given pair of points are (0,0) and (4,3)
Here,
![x_(1)=0 ; y_(1)=0 ; x_(2)=4 ; y_(2)=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5e90z8q8bisgmalp5b0ro7rv87by2dmb0i.png)
We know the slope of an equation is given by y = mx+c
Where “m” is the slope of the line and “c” is the y-intercept
To find the value of m, we use the below given formula
![\mathrm{m}=(y_(2)-y_(1))/(x_(2)-x_(1))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/40um0ixxv38udsd4npw7gxfgs7o6llsdrz.png)
Substituting the values we get,
![\mathrm{m}=(3-0)/(4-0)=(3)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fi1uvw9ojauth4n4f2zl9tfqkdvn15251e.png)
Putting the value of m in the slope intercept form we get,
![y=(3)/(4)x + c](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pdghyotiufm4rej1j9fn33923e4p05mcyj.png)
To find the value of c, we substitute the value of x and y from any two given point. Lets take x = 4 and y = 3
![\begin{array}{l}{3=(3)/(4)(4)+c} \\ {3=3+c} \\ {c=0}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4gwwq0sidg8nkr6krb4yhewqso8ufkux1y.png)
Therefore the slope intercept equation becomes
![y=(3)/(4) x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/szpjaf1no13jf8dcuxmhyo1dtieomn2mqt.png)