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A box rests on top of a flatbed truck. The box has a mass of m = 15 kg. The coefficient of static friction between the box and truck is μs = 0.82, and the coefficient of kinetic friction between the box and truck is μk = 0.66.

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Answer:

Step-by-step explanation:

Given

mass =15 kg

coefficient of static between box and truck
(\mu _s) is =0.82

coefficient of kinetic between box and truck
(\mu _k) is =0.66

Therefore maximum acceleration box can bear without sliding in truck is


a=\mu _s* g=0.82* 9.8=8.036 m/s^2

coefficient of kinetic friction between box and truck does not comes into play because box is rested over truck though truck is moving.

Beyond 8.306 box will slide off the truck.

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