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A Geostationary satellite has an 8kW RF transmission pointed at the earth. How much force does that induce on the spacecraft? (N)

1 Answer

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Answer:

The force induced on the aircraft is 2.60 N

Solution:

As per the question:

Power transmitted,
P_(t) = 8 kW = 8000 W

Now, the force, F is given by:


P_(t) = Force(F)* velocity(v) = Fv (1)

where

v = velocity

Now,

For a geo-stationary satellite, the centripetal force,
F_(c) is provided by the gravitational force,
F_(G):


F_(c) = F_(G)


(mv^(2))/(R) = \frac{GM_(e)m{R^(2)}

Thus from the above, velocity comes out to be:


v = \sqrt{(GM_(e))/(R)}


v = \sqrt{(6.67* 10^(- 11)* 5.979* 10^(24))/(42166* 10^(3))} = 3075.36 m/ s

where

R =
R_(e) + H

R =
\sqrt{GM_(e)((T)/(2\pi))^(2)}

where

G = Gravitational constant

T = Time period of rotation of Earth

R is calculated as 42166 km

Now, from eqn (1):


8000 = F* 3075.36

F = 2.60 N

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