Question

A fluid has a dynamic viscosity of 0.1 Pa.sec, density of 10.0 kg/m^3, pressure of 105 KPa, and temperature of 100 C. Then the kinematic viscosity is equal to______

Answer 1

`\\u =0.01(m^2)/(s)`

Step-by-step explanation:

Hello,

Kinematic viscosity is defined in terms of the dynamic viscosity as follows:

`\\u =(\mu)/(\rho )`

Whereas
`\\u` is the kinematic viscosity,
`\mu` the dynamic viscosity and
`\rho` the density. In this case, the given temperature and pressure are defining both
`\mu` and
`\rho` so they are not included into the aforesaid equation, in such a way, the kinematic viscosity is straightforwardly computed as shown below:

`\\u =(0.1Pa*s)/(10.0kg/m^3) =0.01(kg*(m)/(s^2*m^2)*s)/(kg/m^3) \\\\u =0.01(m^2)/(s)`

Best regards.

Answer 2

The kinematic viscosity is equal to the dynamic viscosity of a fluid divided on its density.

ν = μ / ρ v = 0.1/10 =0.01
`m^(2) /s`

Step-by-step explanation:

The kinematic viscosity is independant of the mass of the fluid as well as its pressure and temperature.