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An engine cylinder has a stroke of 320mm and bore 280MM. Calculate the mass of air contained in the cylinder if it is filled with air at 101.3 KPa at 13C at BDC.

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Answer:

The mass of the air is 0.0243 kg.

Step-by-step explanation:

Step1

Given:

Stroke of the cylinder is 320 mm.

Bore of the cylinder is 280 mm.

Pressure of the air is 101.3 kpa.

Temperature of the air is 13°C.

Step2

Calculation:

Stroke volume of the cylinder is calculated as follows:


V=(\pi )/(4)d^(2)L


V=(\pi)/(4)*((280)/(1000))^(2)*((320)/(1000))

V = 0.0197 m³.

Step3

Assume air an ideal gas with gas constant 287 j/kgK. Then apply ideal gas equation for mass of the air as follows:

PV=mRT


m=(PV)/(RT)


m=(101.3* 1000* 0.0197)/(287* (13+273))

m= 0.0243 kg.

Thus, the mass of the air is 0.0243 kg.

User Martin G
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