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2 1. Scattering cross-section of acrosol particles is 2.5E-12 m , absorption cross-section is 0.45E- .2 12 m Concentration of particles is N 2E7 1/m. Calculate the optical thickness and transmittance of atmosphere at this wavelength if sun zenith angle is 40 degrees and the thickness of aerosol layer is 2.5 km.

User Sur Max
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1 Answer

1 vote

Answer:


T = 3.23 * 10^(-83)

Step-by-step explanation:

thickness of aerosol layer is 2.5 km

zenith angle is 40 degree

we know that


\tau = \epsilon_(ext) . h

where


\epsilon_(ext) = N.\sigma_(ext)


\epsilon_(ext) is extinction coefficient


\sigma_(ext) extiction cross section

N = Concentration


\sigma_(ext) = (2.5 + 0.45)* 10^(-12) m^2


= 2.95 * 10^(-12) m^2


\epsilon_(ext) = 2* 10^7 * 2.95 * 10^(-12) m^2 * m^(-3)


= 5.9 * 10^(-5) m^(1)


\tau = 5.9 * 10^(-5) m^(-1)  * 2.5* 10^3 m


= 14.75* 10^(-2)

transimiitance
T  = e^{(-\tau)/(\mu)}


T  = e^{(- 14.75 * 10^(-2))/(cos 40)}


T = 3.23 * 10^(-83)

User Hang Du
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