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An ideal gas is at a pressure of 1.4 atm and has a volume of 3 L. If the gas is compressed to a volume of 1.0 L while its temperature is held constant, what is the resulting pressure to the nearest tenth of an atm?

User Waffl
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Answer:

The resulting pressure is 4.2 atm. Since it's an ideal gas we use the ideal gas equation to calculate the final pressure.

Step-by-step explanation:

p.v=n.R.T

This applies to both initial and final conditions of the gas, since the temperature is held constant:


(P_(1).V_(1))/(n_(1).R)=(P_(2).V_(2))/(n_(2).R)

And using this equation we find the value of pressure:


(1.4atm.3L)/(1L)=p_(2)

User Ramesh Sambu
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