Question

You wish to prepare a tape-casting slip containing 50 vol% Al2O3 and 50 vol% polyvinyl butyral (PVB) binder. If the density of Al2O3 is 3.98 g/cm and that of PVB is 1.08 g/cm?, how many of grams of PVB are required to produce 1000 g of tape?

Answer 1

Answer: The mass of PVB required to produce 1000 grams of tape is 213.4 grams

Step-by-step explanation:

To calculate the mass of aluminium oxide, we use the equation:

`\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}` .......(1)

• For
  `Al_2O_3`

We are given:

50% (v/v) of
`Al_2O_3`

This means that 50 mL of aluminium oxide is present in 100 mL of tape

Calculating the mass of aluminium oxide by using equation 1:

Density of aluminium oxide =
`3.98 g/cm^3`

Volume of aluminium oxide =
`50mL=50cm^3` (Conversion factor:
`1mL=1cm^3` )

Putting values in equation 1, we get:

`3.98g/cm^3=\frac{\text{Mass of aluminium oxide}}{50cm^3}\\\\\text{Mass of aluminium oxide}=(3.98g/cm^3* 50cm^3)=199g`

Mass of aluminium oxide = 199 g

• For PVB:

We are given:

50% (v/v) of PVB

This means that 50 mL of PVB is present in 100 mL of tape

Calculating the mass of PVB by using equation 1:

Density of PVB =
`1.08 g/cm^3`

Volume of PVB =
`50mL=50cm^3`

Putting values in equation 1, we get:

`1.08g/cm^3=\frac{\text{Mass of PVB}}{50cm^3}\\\\\text{Mass of PVB}=(1.08g/cm^3* 50cm^3)=54g`

Mass of PVB = 54 g

Mass of tape = Mass of aluminium oxide + mass of PVB

Mass of tape = [199 + 54] g = 253 g

To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:

When 253 grams of tape is made, the mass of PVB required is 54 g

So, when 1000 grams of tape is made, the mass of PVB required will be =
`(54)/(253)* 1000=213.4g`

Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams