Question

Charge Q is distributed on a metallic sphere of radius a. What is the electric field at a point a distance r from the center of the sphere? Consider both cases r > a and r < a.

Answer 1

a)E= 0

b)
`E=(Q)/(\varepsilon _o* 4\pi a^2)\ N/C`

Step-by-step explanation:

Given that

Charge Q is distributed on a metallic sphere of radius a

a)r < a.

At a radius r ,from gauss theorem

`E.ds=(q_i)/(\varepsilon _o)`

But in the sphere there is no any charge inside the sphere so

`E.ds=(o)/(\varepsilon _o)`

E.ds = 0

E= 0

b) r > a

At a radius r ,from gauss theorem

`E.ds=(q_i)/(\varepsilon _o)`

`E* 4\pi a^2=(Q)/(\varepsilon _o)`

`E=(Q)/(\varepsilon _o* 4\pi a^2)\ N/C`