Answer:
![62.7 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/2oe6m731licfwykcihdwh621qlvnhnrggz.png)
Step-by-step explanation:
Assuming the dragster accelerates at constant rate, the equation that describes the distance travelled by the dragster after time t is
![d(t) = ut + (1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/71a79wjkvrg8hl0zg6mgw6turoblk95exn.png)
where
u is the initial velocity
a is the acceleration
If we assume that the dragster starts from rest,
u = 0
And we also know that at t = 3.58 s, the distance covered is
d = 402 m
Solving the formula for a, we find the acceleration:
![d=(1)/(2)at^2\\a=(2d)/(t^2)=(2(402))/((3.58)^2)=62.7 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/220jmcqmehw815ul1cr0bb04ytxvnmk1t1.png)