Answer
given,
head gradient = 0.05
hydraulic conductivity = 1 m/d
effective porosity = 0.2
from Darcy's law
V = k i
v = 1 × 0.05
= 0.05 m/day
seepage velocity



specific discharge

q = 1 × 0.05
q = 0.05 m/day
b) Q = A V
=20 × 850 × 0.05
Q = 850 m³/day
c) time require to move 75 m


t = 300 days