Question

What are the potential solutions of In(x^2 - 25) = 0?

Answer 1

-3 on edg

Explanation:

Answer 2

`\boxed{\boxed{\pink{\bf \leadsto The \ Solution \ of \ the \ given \ equation \ is\ √(26)\ or \ -√(26)}}}`

Explanation:

We need to find the solution of the given logarithmic equation. So the given equation is ,

`\bf \implies ln ( x^2-25) = 0`

Using the Properties of log we can write this as ,

`\bf \implies e^(ln(x^2-25)) = e^0 \:\:\bigg\lgroup \red{\bf Here \ e \ is \ Euler's \ Number }\bigg\rgroup \\\\\bf\implies x^2-25 = e^0 \\\\\bf\implies x^2-25 = 1 \\\\\bf\implies x^2=25+1\\\\\bf\implies x^2=26 \\\\\bf\implies x = √(26) \\\\\bf\implies\boxed{\red{\bf x = √(26),-√(26)}}`

Hence the Solution of the given equation is √26 or -√26.