Question

You do an experiment in which you need 0.5 mole of tyrosine (C9H11NO3) .

How many grams must you weigh out?


65 g


90.5 g


181 g


272 g

Answer 1

90.5 g

Step-by-step explanation:

we know 1 mole of thyrosine = 181g

so 0.5 mole thyrosine =181*0.5

=90.5g

Answer 2

Answer: Option (b) is the correct answer.

Step-by-step explanation:

Number of moles given are 0.5 mol and molar mass of tyrosine (
`C_(9)H_(11)NO_(3)`) is 181.19 g/mol.

Therefore, calculate the mass of given molecules follows.

No. of moles of tyrosine =
`\frac{mass}{\text{molar mass}}`

0.5 mol =
`(mass)/(181.19 g/mol)`

mass = 90.595 g

Therefore, we can conclude that mass of 0.5 mole of tyrosine (
`C_(9)H_(11)NO_(3)`) is 90.5 g.