Answer:
- Graph B has one real root.
- Graph A has a negative discriminant
- Graph C has an equation with the coefficients a=1, b=4, c=-2.
Explanation:
The number of real roots is the number of places where the graph intersects the x-axis. When the discriminant is negative, there are none. Graph A does not cross the x-axis, so has a negative discriminant.
Graph B intersects the x-axis at one point, so it has one real root.
Graph C has two real roots, consistent with the positive discriminant associated with the given coefficients:
![d=b^2-4ac=4^2-4(1)(-2)=16+8=24](https://img.qammunity.org/2020/formulas/mathematics/high-school/ftq7oe705hgavae1fra415169n7rt5jnxy.png)
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For quadratic ...
![y=ax^2+bx+c](https://img.qammunity.org/2020/formulas/mathematics/middle-school/681jf4lsjwxd9lmjd27bh82m6tps71a0gl.png)
the discriminant is ...
![d=b^2-4ac](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69x45uvjnlbwuq95o8iqup1af669o3j6zy.png)
and the roots are ...
![x=(-b\pm√(d))/(2a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/sminkgqr7mruejjjldua0n51s2wax2f7nv.png)
Then the roots are only real when the discriminant is non-negative. The square root function will not give real values for a negative argument.