Question

3

50
Small rockets are used to make tiny corrections to the speed of a satellite. If a rocket has a thrust of
35 N and is used to change the velocity of a 72000-kg satellite by 63 cm/s, for how long should it be
fired?
Variables:
Equations:
Answers

Answer 1

The rocket should be fired for 129600 seconds.

Why?

We can calculate for how long should the rocket be fired by using the following equation:

`Force=mass*aacceleration=mass*(v-v_(o))/(time) \\\\time=(mass*(v-v_(o)))/(Force)`

From the statement we know:

- Initial speed equal to zero.

- Force equal to 272N.

- Final speed (for the moment) equal to 62 m/s.

- Mass equal to 72000 Kg.

So, substituting and calculating, we have:

`time=(mass*(v-v_(o)))/(Force)`

`time=(mass*(v-v_(o)))/(Force)\\\\time=(72000*(63(m)/(s) -0))/(35(Kg.m)/(s^(2)))=129600s`

Hence, we have:

Variables: Time

Equations:

`Force=mass*aacceleration=mass*(v-v_(o))/(time) \\\\time=(mass*(v-v_(o)))/(Force)`

Answers: The rocket should be fired for 129600 seconds.

Have a nice day!