Final answer:
The magnitude and angle of the displacement vector of the wall clock's minute hand for different time intervals can be determined using trigonometry.
Step-by-step explanation:
To determine the magnitude and angle of the displacement vector of the wall clock's minute hand for different time intervals, we can use trigonometry.
(a) For the time interval from a quarter after the hour to half past, the magnitude of the displacement vector is 8 cm (half the length of the minute hand), and the angle can be calculated as 45 degrees counterclockwise from the +x direction.
(b) For the next half hour, the magnitude remains the same at 8 cm, and the angle increases by 30 degrees to a total of 75 degrees counterclockwise.
(e) For the hour after that, the magnitude remains the same at 8 cm, and the angle increases by another 30 degrees to a total of 105 degrees counterclockwise.