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Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?

–negative StartFraction 7 Over 3 EndFraction
–negative StartFraction 9 Over 7 EndFraction
–negative StartFraction 7 Over 9 EndFraction
–negative StartFraction 3 Over 7 EndFraction

2 Answers

3 votes

Answer:

The answer is B

User Christopher Helck
by
7.8k points
3 votes

Answer:


\Huge\boxed{\mathsf{-(9)/(7) }}}

Explanation:

SLOPE FORMULA:


\displaystyle \mathsf{(Y_2-Y_1)/(X_2-X_1)=(RISE)/(RUN)  }

Y2=(-3)

Y1=6

X2=5

X1=(-2)

Solve.


\displaystyle \mathsf{((-3)-6)/(5-(-2))=((-3)-6)/(5+2)= (-9)/(7)=\boxed{\mathsf{-(9)/(7)}  }}

The slope is -9/7.

User Zuma
by
9.3k points

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