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Chlorine gas has a density of 0.03 lbm/ft^3 at a given temperature. How big would a tank need to be in gallons to hold 200 lbm of chlorine? Check your unit conversions with a unit converter App (ConvertPad in Droid is very good).

1 Answer

4 votes

Answer:

We need a tank of volume 49866.6168 gallon

Step-by-step explanation:

We have given mass of chlorine m = 200 lbm

Density of chlorine
d=0.03lbm/ft^3

We know that mass = density × volume

So volume
=(mass)/(density)=(200)/(0.03)=6666.66ft^3

We know that 1
ft^3 = 7.480 gallon

So 6666.66
ft^3 = 6666.66×7.480 = 49866.6168 gallon

So we need a tank of volume 49866.6168 gallon

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