Answer:
We need a tank of volume 49866.6168 gallon
Step-by-step explanation:
We have given mass of chlorine m = 200 lbm
Density of chlorine
![d=0.03lbm/ft^3](https://img.qammunity.org/2020/formulas/engineering/college/hocxgdpwwuaqop6g90m3tmlu5r5jel9k5w.png)
We know that mass = density × volume
So volume
![=(mass)/(density)=(200)/(0.03)=6666.66ft^3](https://img.qammunity.org/2020/formulas/engineering/college/j296cjnvgh1ikg9zyeb155f6h0aj9f5tpq.png)
We know that 1
= 7.480 gallon
So 6666.66
= 6666.66×7.480 = 49866.6168 gallon
So we need a tank of volume 49866.6168 gallon