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Write the expression for work performed by expansion/compression. Define all terms in this expression. Give the SI and English units for each term. an ideal gas during isothermal

User Yogendra
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1 Answer

6 votes

Answer:


W=P_1V_1\ ln(V_2)/(V_1)

Step-by-step explanation:

Lets take

At initial position


Pressure = P_1


Volume = V_1

At final position


Pressure = P_2


Volume = V_2

SI unit


Pressure =N/m^2


Volume =m^3

English units


Pressure =lb/in^2


Volume =in^3

For expansion process:

As we know that work done given as


W=\int P.dV

We know that for isothermal process

P.V = C


P_1V_1=P_2V_2=C


W=\int_(V_1)^(V_2)(P_1V_1)/(V).dV


W=P_1V_1\ ln(V_2)/(V_1)

Expression for expansion and for compression will be same.

User Jinbom Heo
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