Answer:
![W=P_1V_1\ ln(V_2)/(V_1)](https://img.qammunity.org/2020/formulas/engineering/college/85dgdo29u1sab5qab67zf33hf03axgkng7.png)
Step-by-step explanation:
Lets take
At initial position
![Pressure = P_1](https://img.qammunity.org/2020/formulas/engineering/college/bcfefvw29vnu0lylqbz19xbpk8s5kldkf3.png)
![Volume = V_1](https://img.qammunity.org/2020/formulas/engineering/college/st2blw8fq8yllp8wj20suzhx3cioz86gj9.png)
At final position
![Pressure = P_2](https://img.qammunity.org/2020/formulas/engineering/college/17qkx0080f85jd9hx72obu33ejrjt1lk5y.png)
![Volume = V_2](https://img.qammunity.org/2020/formulas/engineering/college/2zhp2y2kdqg6m48v5yczxy8nhe1mou48u2.png)
SI unit
![Volume =m^3](https://img.qammunity.org/2020/formulas/engineering/college/jndfa7933njn1njroosdfcqzjlkqgfhzob.png)
English units
![Volume =in^3](https://img.qammunity.org/2020/formulas/engineering/college/w5iq9jfwdi4hh9wbywex35pu1y08owju3h.png)
For expansion process:
As we know that work done given as
![W=\int P.dV](https://img.qammunity.org/2020/formulas/engineering/college/b77tyhjjyw7b44jxi15einn1ftsreh4qjh.png)
We know that for isothermal process
P.V = C
![P_1V_1=P_2V_2=C](https://img.qammunity.org/2020/formulas/engineering/college/tk712vg43hbt5ikrphhz7zi0df2634qzz0.png)
![W=\int_(V_1)^(V_2)(P_1V_1)/(V).dV](https://img.qammunity.org/2020/formulas/engineering/college/krt0tg9rq2xd9f6gtuhsjhfs5ozlwvdvt7.png)
![W=P_1V_1\ ln(V_2)/(V_1)](https://img.qammunity.org/2020/formulas/engineering/college/85dgdo29u1sab5qab67zf33hf03axgkng7.png)
Expression for expansion and for compression will be same.