Answer:
Tension in wire will be
![16* 10^3N-m](https://img.qammunity.org/2020/formulas/engineering/college/ojgp1axbwzlwrokn99tn4mjx8kfvlfl438.png)
Step-by-step explanation:
We have given seed of the transverse wave v = 400 m/sec
Linear density = 0.10 g/cm
We know that 1 gram = 0.001 kg
And 1 cm = 0.01 m
So
![0.1g/cm =(0.1* 10^(-3)kg)/(10^(-2)m)=10^(-2)kg/m](https://img.qammunity.org/2020/formulas/engineering/college/a48hn36auj9f14st6ywh1h5ubtwupxtjba.png)
We know that speed of wave is given by
, here T is tension in the wire
So
![400=\sqrt{(T)/(10^(-2))}](https://img.qammunity.org/2020/formulas/engineering/college/g1vvg7kukglwvybw5ywjq177bhda8x3i4p.png)
Squaring both side
![16* 10^4=(T)/(0.1)](https://img.qammunity.org/2020/formulas/engineering/college/d4dvru1rmz17d0myzxyde8yqnuftzkndhh.png)
T =
![16* 10^3N-m](https://img.qammunity.org/2020/formulas/engineering/college/ojgp1axbwzlwrokn99tn4mjx8kfvlfl438.png)
So tension in wire will be
![16* 10^3N-m](https://img.qammunity.org/2020/formulas/engineering/college/ojgp1axbwzlwrokn99tn4mjx8kfvlfl438.png)