128k views
2 votes
A speedy rabbit is hopping to the right with a velocity of 4.0m/s when it sees a carrot in the distance. The rabbit speeds up to its maximum velocity of 13m/s with a constant acceleration 2.0m/s2 rightward.

How many seconds does it take the rabbit to speed up from 4.0m/s to 13m/s

2 Answers

4 votes

Answer:

t = 4.5 seconds

Explanation:

initial velocity = 4.0 m/s

final velocity = 13 m/s

acceleration = 2.0 m/s2

t = (final velocity - initial velocity) / acceleration

t = (13 - 4.0) / 2.0

t = 4.5 seconds

User Mockingbird
by
8.3k points
4 votes

Answer:

4.5 sec.

Explanation:

We know that:


v_(0)=4.0m/s


v_(f)=13m/s


a=2.0m/s^(2)

Now, to calculate the time, we must use this equation:


v_(f)=v_(0)+at\\v_(f)-v_(0)=at\\(v_(f)-v_(0))/(a)=t \\t=(13m/s-4m/s)/(2m/s^(2) ) =4.5sec

This means that the rabbit needs 4.5 seconds to speed up from 4m/s to 13 m/s. In this type of problem, we just need to read carefully if there are initial (
v_(0)) and final speed (
v_(f)), and acceleration, because that's the case when we use the equation showed.

User Yorick
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.