105k views
5 votes
If the SOD is 54 inches, the OID 8 inches, and the object length 6 inches, what is the image length?

User Jaden Gu
by
7.9k points

1 Answer

4 votes

Answer:

image length is 6.89 inches

Explanation:

Data provide:

SOD = 54 inches

OID = 8 inches

Object length = 6 inches

Now,

magnification =
\frac{\textup{Image length}}{\textup{Object length}}=-\frac{\textup{SID}}{\textup{SOD}}

also,

SID = SOD + OID

or

SID = 54 + 8 = 62 inches

Therefore,


\frac{\textup{Image length}}{\textup{6}}=-\frac{\textup{62}}{\textup{54}}

or

Image length = - 1.148 × 6

or

Image length = - 6.89 inches

Here negative sign depicts the inverted image

Hence,

The Magnitude of the image length is 6.89 inches

User Sandthorn
by
9.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.