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If the SOD is 54 inches, the OID 8 inches, and the object length 6 inches, what is the image length?

User Jaden Gu
by
5.3k points

1 Answer

4 votes

Answer:

image length is 6.89 inches

Explanation:

Data provide:

SOD = 54 inches

OID = 8 inches

Object length = 6 inches

Now,

magnification =
\frac{\textup{Image length}}{\textup{Object length}}=-\frac{\textup{SID}}{\textup{SOD}}

also,

SID = SOD + OID

or

SID = 54 + 8 = 62 inches

Therefore,


\frac{\textup{Image length}}{\textup{6}}=-\frac{\textup{62}}{\textup{54}}

or

Image length = - 1.148 × 6

or

Image length = - 6.89 inches

Here negative sign depicts the inverted image

Hence,

The Magnitude of the image length is 6.89 inches

User Sandthorn
by
6.3k points